Digital Modulation Techniques Quiz | Digital Modulation Techniques Multiple Choice Questions and Answers

(1) In uniform quantization process
[A] The step size remains same
[B] Step size varies according to the values of the input signal
[C] The quantizer has linear characteristics
[D] Both a and c are correct
Answer: Both a and c are correct
(2) Timing jitter is
[A] Deviation in location of the pulses
[B] Change in frequency
[C] Change in amplitude
[D] All of the above
Answer: Deviation in location of the pulses

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(3) Probability density function defines
[A] Probability of error
[B] Amplitudes of random noise
[C] Density of signal
[D] All of the above
Answer: Amplitudes of random noise
(4) Pulse shaping is done
[A] after line coding and modulation of signal
[B] by limiting the bandwidth of transmission
[C] to control Inter Symbol Interference
[D] All of the above
Answer: All of the above
(5) For a noise to be white Gaussian noise, the optimum filter is known as
[A] Matched filter
[B] Bessel filter
[C] Base band filter
[D] Low pass filter
Answer: Matched filter
(6) The time interval over which the received signal may be sampled without error may be explained by
[A] Height of the eye opening of eye pattern
[B] Rate of closure of eye of eye pattern
[C] Width of eye opening of eye pattern
[D] All of the above
Answer: Width of eye opening of eye pattern
(7) Eye pattern is
[A] Resembles the shape of human eye
[B] May be seen on CRO
[C] Is used to study ISI
[D] All of the above
Answer: All of the above
(8) Advantages of using AMI
[A] May be used for longer distance
[B] Prevents build-up of DC
[C] Needs least power as due to opposite polarity
[D] All of the above
Answer: All of the above
(9) In Alternate Mark Inversion (AMI) is
[A] 0 is encoded as no pulse and 1 is encoded as negative pulse
[B] 0 is encoded as negative pulse and 1 is encoded as positive pulse
[C] 0 is encoded as positive pulse and 1 is encoded as negative pulse
[D] 0 is encoded as no pulse and 1 is encoded as positive or negative pulse
Answer: 0 is encoded as no pulse and 1 is encoded as negative pulse
(10) For M equally likely messages, M>>1, if the rate of information R > C, the probability of error is
[A] Close to unity
[B] Unknown
[C] Arbitrarily small
[D] Not predictable
Answer: Close to unity
(11) For M equally likely messages, M>>1, if the rate of information R ≤ C, the probability of error is
[A] Not predictable
[B] Close to unity
[C] Arbitrarily small
[D] Unknown
Answer: Arbitrarily small
(12) The negative statement for Shannon’s theorem states that
[A] If R > C, the error probability increases towards Unity
[B] If R < C, the error probability is very small
[C] Both a & b
[D] None of the above
Answer: If R > C, the error probability increases towards Unity
(13) According to Shannon Hartley theorem,
[A] The channel capacity becomes infinite with infinite bandwidth
[B] The channel capacity does not become infinite with infinite bandwidth
[C] Has a tradeoff between bandwidth and Signal to noise ratio
[D] Both B and C are correct
Answer: Both B and C are correct
(14) The channel capacity is
[A] The maximum information transmitted by one symbol over the channel
[B] Information contained in a signal
[C] The amplitude of the modulated signal
[D] All of the above
Answer: The maximum information transmitted by one symbol over the channel
(15) For M equally likely messages, the average amount of information H is
[A] H = log2M
[B] H = 2log10M
[C] H = log10M
[D] H = log10M2
Answer: H = log2M
(16) The capacity of Gaussian channel is
[A] C = 2B(1+S/N) bits/s
[B] C = B2(1+S/N) bits/s
[C] C = B(1+S/N) bits/s
[D] C = B(1+S/N)2 bits/s
Answer: C = B(1+S/N) bits/s
(17) The probability density function of a Markov process is
[A] p(x1,x2,x3…….xn) = p(x1)p(x2/x1)p(x3/x2)…….p(xn/xn-1)
[B] p(x1,x2,x3……xn) = p(x1)p(x2 * x1)p(x3 * x2)……..p(xn * xn-1)
[C] p(x1,x2,x3…….xn) = p(x1)p(x1/x2)p(x2/x3)…….p(xn-1/xn)
[D] p(x1,x2,x3……xn) = p(x1)p(x2)p(x3)…….p(xn)
Answer: p(x1,x2,x3…….xn) = p(x1)p(x2/x1)p(x3/x2)…….p(xn/xn-1)
(18) Orthogonality of two codes means
[A] The integrated product of two same code words is zero
[B] The integrated product of two different code words is zero
[C] The integrated product of two different code words is one
[D] None of the above
Answer: The integrated product of two different code words is zero
(19) The Golay code (23,12) is a codeword of length 23 which may correct
[A] 8 errors
[B] 2 errors
[C] 3 errors
[D] 5 errors
Answer: 3 errors
(20) The prefix code is also known as
[A] Convolutional code
[B] Parity bit
[C] Instantaneous code
[D] Block code
Answer: Instantaneous code

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