Consider a system of three identical and distinguishable non-interacting particles and three available nondegenerate single particle energy levels having energies

Q. Consider a system of three identical and distinguishable non-interacting particles and three available nondegenerate single particle energy levels having energies 0, e and 2e. The system is in contact with a heat bath of temperature T K. A total energy of 2ɛ is shared by these three particles. The number of ways the particles can be distributed is               .

Solution:

For a three-state distinguishable system, Total Energy of the system = Ʃ Energy = E1+ E2+ E3.

Let, the three possible systems are A, B, C. Then, the possible arrangements for the total energy of 2ε (where only one system will have 2ε energy) will be 6.