Find the reflection of a point (2, –5) when mirror is placed on y = –2.5?

Find the reflection of a point (2, –5) when mirror is placed on y = –2.5?

a) (2, 0)

b) (0, 2)

c) (0.5, –5)

d) (5, –0.5)

Sol:

As shown by figure

Point P = (2, –5) is shown in fourth quadrant is at y = – 2.5

Difference of mirror with P

y = –5 – (–2.5) = –2.5 cm

x remain same as mirror is on y axis hence refection point of P is =

= (2, 0)