I. 15×2 – 46x + 32 = 0 II. 3y2 – 17y + 24 = 0

Q) I. 15×2 – 46x + 32 = 0 II. 3y2 – 17y + 24 = 0

a)            x> y

b)            y> x

c)            x ≥ y

d)            x ≤ y

e)            x = y or relation cannot be established

Sol:

I.

15×2 – 46x + 32 = 0

15×2 – 30x – 16x + 32 = 0

15x(x – 2) – 16(x – 2) = 0

x = 16/15 or 2

II.

3y2 – 17y + 24 = 0

3y2 – 9y – 8y + 24 = 0

3y(y – 3) – 8(y – 3) = 0

y = 8/3 or 3

Hence, x < y