I. x2 – 47x + 480 = 0 II. y = √(31y – 240)

Q. I. x2 – 47x + 480 = 0

II. y = √(31y – 240)

a)            x = y or relation cannot be established

b)            y> x

c)            x ≥ y

d)            x ≤ y

e)            x> y

Sol:

I.

x2 – 47x + 480 = 0

x2 – 32x – 15x + 480 = 0

x(x – 32) – 15(x – 32) = 0

x = 15 or 32

II.

y = √(31y – 240)

y2 – 31y + 240 = 0

y2 – 15y – 16y + 240 = 0

y(y – 15) – 16(y – 15) = 0

y = 16 or 15

Hence, the relationship between x and y cannot

be established