In ∆ABC, AD ⊥ BC, if BD = x units, then x is
In ∆ABC, AD ⊥ BC, if BD = x units, then x is:
Sol:
a² + x² – 2ax + h² = b² …(ii)
from subtracting (i) from (ii)
a² – 2ax = b² – c²
In ∆ABC, AD ⊥ BC, if BD = x units, then x is:
Sol:
a² + x² – 2ax + h² = b² …(ii)
from subtracting (i) from (ii)
a² – 2ax = b² – c²
