In the given figure, ‘ O’ is the centre of circle and AB = BC and ∠AOB = 90°, then ∠a is

In the given figure, ‘ O’ is the centre of circle and AB = BC and ∠AOB = 90°, then ∠a is

In the given figure, ‘ O’ is the centre of circle and AB = BC and ∠AOB = 90°, then ∠a is.

a) 35°

b) 55°

c) 45°

d) 65°

Sol:

∆AOB ∆COB

AB = BC

AO = CO

OB = common

⇒ ∠BOC = 90° as ∠AOB = 90°

⇒ AC = diameter ⇒ ∠ABC = 90°

∠ABO = 45°= ∠a

quantitative aptitude
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