Study the following graph and answer the questions. The following bar graph shows the dimensions of cone, cylinder and sphere in cm

Study the following graph and answer the questions. The following bar graph shows the dimensions of cone, cylinder and sphere in cm

Directions: Study the following graph and answer the questions

The following bar graph shows the dimensions of cone, cylinder and sphere in cm.

Now 3 more 3D figure cube, prisms and pyramid notes are given Notes:

1.            The length of the cube is similar with the diameter of the sphere

2.            The height of prism is similar to the height of a cone.

3.            The side of the prism is 3/5th the radius of the cone.

4.            The height of the pyramid is similar with the radius of the sphere

5.            The side of the pyramid is similar with 4/5th of height of the cylinder

*             All figures are solid

*             Base of the prism = square

*             Base of the pyramid is equilateral triangle

1) Find the ratio of the volume of the cone to pyramid?

A. 54:53√(3)

B. 53:55√(3)

C. 57:54 √(3)

D. 165:28 √(3)

E. None of these

Sol:

The volume of the cone= 1/3 *22/7*r2*h

=1/3 *22/7* 102*18 cm3

The volume of pyramid

=1/3* area of base * height

=1/3 *√(3)/4 *162 *15 cm3

So the ratio will be

=> 1/3 *22/7*100*18:1/3*√(3)*64*15

= 165 :28 √(3)

2) Find the ratio of volume of cylinder to prism.

A. 12340:567

B. 14360:576

C. 14300:687

D. 14080:567

E. 15400:786

Sol:

The volume of the cylinder = 22/7 *162 *20cm3

Volume of the prism= area of base * height

As the area of the prisms is square

So area of the base= 6*6=36 cm2

So the volume= 36 *18 cm3

So the required ratio= 22/7*16*16*20:36*18

=14080:567

3) Find the difference between the total surfacearea of the sphere and cylinder?

A. 687 cm2

B. 753 cm2

C. 782 cm2

D. 792 cm2

E. 497 cm2

Sol:

The total surfacearea of the sphere= 4 *22/7

*15*15

=88*225/7=2828.57 cm2

The total area of the cylinder= perimeter of the

base *height+2* base area

=2*22/7*16*20 +2*22/7 *16*16

=22/7(640+512)

=22/7(1152)

=3620.57cm2

So, the required difference= 3620.57-

2828.57=792cm2

4) The total surfacearea of the cone is how much percent more or less than the total surfacearea of the cube?

A. 99.5% more

B. 95.4% less

C. 94.4% less

D. 97.6% less

E. 82.19% less

Sol:

The radius of the cone= 10cm, and the height of

the cone=18cm

So, the slant height= √(182+102)

=√(324+100) =√(424)=20.59cm

So, the totalsurface area of the cone=22/7

*10*20.6 +22/7 *10*10

=22/7(206+100)=22/7 *306=961.71 cm2

The total surface area of cube= 6* length *

length

=5400 cm2

So the required percentage=(5400-961.71)/5400

*100

=82.19% less

Gkseries: Gkseries.com is a premier website to provide complete solution for online preparation of different competitive exams like UPSC, SBI PO, SBI clerical, PCS, IPS, IAS, IBPS PO, IBPS Clerical exam etc. & other graduate and post-graduate exams. Learn more on about us page