Q. There are three mixtures of milk and water named as P, Q, and R. A new mixtures M is formed by mixing 120 ml from mixture P and 96 ml from mixture Q. Now 48 ml mixture from R M in which Milk and water ratio is 2:1 is mixed with 54 ml of mixture M to form new mixture N, such that ratio of milk and water in mixture N becomes 65:37. The ratio of milk and water in mixture P initially is L: K respectively, and in mixture Q is 5:3 respectively. Find the value of [6(L + K) \/ (2L + K)].<\/p>\n\n\n\n
A.7.5<\/p>\n\n\n\n
B.3.75<\/p>\n\n\n\n
C.3.5<\/p>\n\n\n\n
D.4.5<\/p>\n\n\n\n
E. None of these<\/p>\n\n\n\n
Ans: 3.75<\/p>\n\n\n\n
Sol:<\/p>\n\n\n\n
54 ml of mixture M mixed with 48 ml of mixture
R, to form mixture N, in which ratio of milk and
water = 65:37
Total milk in mixture N = 65\/102 x (54 + 48) = 65
ml
Milk taken from mixture M = 65 \u2013 2\/3 x 48 = 33
ml
Total water in mixture N = 37\/102 x 102 = 37 ml
Water taken from mixture M = 37 \u2013 1\/3 x 48 = 21
Ratio of milk and water in mixture M = 33:21 =
11:7
Total quantity of mixture M = 120 + 96 = 216 ml
Amount of milk in mixture M = 11\/18 x 216 = 132
ml
Amount of water in Mixture M = 216 \u2013 132 = 84
ml<\/p>\n\n\n\n
Amount of milk taken from P = 132 \u2013 5\/8 x 96 =
72 ml
Amount of water taken from P = 84 \u2013 3\/8 x 96 =
48 ml
Ratio of milk and water in P = 72:48 = 3:2
Required value = [6 x (3 + 2) \/ (2 x 3 + 2)] = 3.75
Hence answer is option B<\/p>\n","protected":false},"excerpt":{"rendered":"
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