Vessel A contains a mixture of milk and water and vessel B contains a mixture of 240 liters mixture of milk and water in the ratio of 7:5 and the total quantity of vessel A and 60% of the mixture of vessel B are mixed together in a new empty vessel, then the ratio of the milk to water becomes 6:5. Find the ratio of the quantity of milk to water in vessel A initially, if the quantity of milk in vessel A is 4 liters less than that of water in vessel A.<\/p>\n\n\n\n
a) 8:7<\/p>\n\n\n\n
b) 5:4<\/p>\n\n\n\n
c) 9:10<\/strong><\/p>\n\n\n\n d) 4:5<\/p>\n\n\n\n e) None of these<\/p>\n\n\n\n Sol:<\/p>\n\n\n\n Let the quantity of milk and water in vessel A is x<\/p>\n\n\n\n and (x + 4) liters respectively.<\/p>\n\n\n\n 60% of the quantity of mixture in vessel B = 240 *<\/p>\n\n\n\n 60\/100 = 144 liters<\/p>\n\n\n\n (x + 144 * 7\/12)\/(x + 4 + 144 * 5\/12) = 6\/5<\/p>\n\n\n\n (x + 84)\/(x + 4 + 60) = 6\/5<\/p>\n\n\n\n (x + 84)\/(x + 64) = 6\/5<\/p>\n\n\n\n 5x + 420 = 6x + 384<\/p>\n\n\n\n x = 36 liters<\/p>\n\n\n\n Quantity of milk in vessel A = 36 liters<\/p>\n\n\n\n Quantity of water in vessel A = 36 + 4 = 40 liters<\/p>\n\n\n\n Required ratio = 36:40 = 9:10<\/p>\n","protected":false},"excerpt":{"rendered":" Vessel A contains a mixture of milk and water and vessel B contains a mixture of 240 liters mixture of milk and water in the ratio of 7:5 and the total quantity of vessel A and 60% of the mixture of vessel B are mixed together in a new empty vessel, then the ratio of 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