The age of P after 8 years is equal to the present age of Q and the present age of P is 8\/9th of the present age of R and the average of the ages of Q and R after 4 years is 42 years. Find sum of the present age of P and the age of Q before 6 years.<\/p>\n\n\n\n
a) 66 years<\/strong><\/p>\n\n\n\n b) 60 years<\/p>\n\n\n\n c) 72 years<\/p>\n\n\n\n d) 45 years<\/p>\n\n\n\n e) None of these<\/p>\n\n\n\n Sol:<\/p>\n\n\n\n P = 8\/9 * R = 8R\/9<\/p>\n\n\n\n 8R\/9 + 8 = Q —- (1)<\/p>\n\n\n\n Q + 4 + R + 4 = 42 * 2<\/p>\n\n\n\n Q + R = 84 \u2013 8<\/p>\n\n\n\n Q + R = 76 —- (2)<\/p>\n\n\n\n From (1) and (2),<\/p>\n\n\n\n 8R\/9 + 8 + R = 76<\/p>\n\n\n\n 8R\/9 + R = 68<\/p>\n\n\n\n (8R + 9R)\/9 = 68<\/p>\n\n\n\n 17R\/9 = 68<\/p>\n\n\n\n R = 36 years<\/p>\n\n\n\n P = 8 * 36\/9 = 32 years<\/p>\n\n\n\n Q + 36 = 76<\/p>\n\n\n\n Q = 40 years<\/p>\n\n\n\n Required sum = 32 + (40 \u2013 6) = 32 + 34 = 66 years<\/p>\n","protected":false},"excerpt":{"rendered":" The age of P after 8 years is equal to the present age of Q and the present age of P is 8\/9th of the present age of R and the average of the ages of Q and R after 4 years is 42 years. 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