Direction: Following question contains two equations as I and II. You have to solve both equations and determine the relationship between them and give answer as,<\/p>
Q.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/p>
I: x2 – x – 12 = 0 II: y2 – 2y -15 = 0<\/p>
A.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 x < y<\/p>
B.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 x > y<\/p>
C.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 x \u2264 y<\/p>
D.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 x \u2265 y<\/p>
E.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Relationship between x and y cannot be determined<\/b><\/p>
Sol:<\/p>
From I =>x2<\/sup> – x – 12 = 0 <\/p> =>x2<\/sup> \u2013 4x + 3x – 12 = 0 <\/p> =>x(x \u2013 4) +3(x \u2013 4) = 0 <\/p> => (x \u2013 4) (x + 3) = 0 <\/p> => x = 4, -3<\/p> From II =>y2<\/sup> – 2y – 15 = 0 <\/p> =>y2<\/sup> – 5y + 3y – 15 = 0 <\/p> =>y(y \u2013 5) +3(y – 5) = 0 <\/p> => (y \u2013 5) (y + 3) = 0 <\/p> => y = 5, -3 <\/p> Hence, relationship between x and y cannot be determined<\/p> <\/p>\n","protected":false},"excerpt":{"rendered":" Direction: Following question contains two equations as I and II. You have to solve both equations and determine the relationship between them and give answer as, Q.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 I: x2 – x – 12 = 0 II: y2 – 2y -15 = 0 A.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 x < y B.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 x > y C.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 x \u2264 y D.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 […]<\/p>\n","protected":false},"author":419,"featured_media":163750,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[5138],"tags":[5139],"offerexpiration":[],"class_list":["post-163749","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-quantitative-aptitude","tag-quantitative-aptitude"],"_links":{"self":[{"href":"https:\/\/www.gkseries.com\/blog\/wp-json\/wp\/v2\/posts\/163749","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.gkseries.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.gkseries.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.gkseries.com\/blog\/wp-json\/wp\/v2\/users\/419"}],"replies":[{"embeddable":true,"href":"https:\/\/www.gkseries.com\/blog\/wp-json\/wp\/v2\/comments?post=163749"}],"version-history":[{"count":1,"href":"https:\/\/www.gkseries.com\/blog\/wp-json\/wp\/v2\/posts\/163749\/revisions"}],"predecessor-version":[{"id":163751,"href":"https:\/\/www.gkseries.com\/blog\/wp-json\/wp\/v2\/posts\/163749\/revisions\/163751"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.gkseries.com\/blog\/wp-json\/wp\/v2\/media\/163750"}],"wp:attachment":[{"href":"https:\/\/www.gkseries.com\/blog\/wp-json\/wp\/v2\/media?parent=163749"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.gkseries.com\/blog\/wp-json\/wp\/v2\/categories?post=163749"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.gkseries.com\/blog\/wp-json\/wp\/v2\/tags?post=163749"},{"taxonomy":"offerexpiration","embeddable":true,"href":"https:\/\/www.gkseries.com\/blog\/wp-json\/wp\/v2\/offerexpiration?post=163749"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}