Find the sum of the numbers between 550 and 700 such that when they are divided by 12, 16 and 24, leave remainder 5 in each case.<\/p>\n\n\n\n
a) 1998<\/p>\n\n\n\n
b) 1887<\/strong><\/p>\n\n\n\n c) 1788<\/p>\n\n\n\n d) 1884<\/p>\n\n\n\n Sol:<\/p>\n\n\n\n \u21d2 LCM of 12, 16, and 24 = 48 <\/p>\n\n\n\n Multiple of 48 bigger than 550 which leaves remainder 5 are <\/p>\n\n\n\n \u21d2 1st Number = 48 x 12 + 5 = 581 <\/p>\n\n\n\n \u21d2 2nd Number = 48 x 13 + 5 = 629 <\/p>\n\n\n\n \u21d2 3rd Number = 48 x 14 + 5 = 677 <\/p>\n\n\n\n \u21d2 Sum of these numbers are = 581 + 629 + 677 = 1887 <\/p>\n\n\n\n \u21d2 Hence, The sum of the numbers are 1887.<\/p>\n","protected":false},"excerpt":{"rendered":" Find the sum of the numbers between 550 and 700 such that when they are divided by 12, 16 and 24, leave remainder 5 in each case. a) 1998 b) 1887 c) 1788 d) 1884 Sol: \u21d2 LCM of 12, 16, and 24 = 48 Multiple of 48 bigger than 550 which leaves remainder 5 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