Automata Theory Objective Questions Answers | Page-3

21 TM is more powerful than FSM because
[A] it has no finite state control
[B] the tape movement is confined to one direction
[C] it has the capability to remember arbitrary long sequences of input symbols
[D] none of the above

Answer: Option [C]
22 Choose the correct statements.
[A] A ={anbn | n = 0,1,2,3,………} is a regular language.
[B] L(A*B*) ∩ B gives the set A.
[C] The set B, consisting of all strings made up of only a’s and b’s having equal number of a’s and b’s defines a regular language.
[D] None of the above

Answer: Option [B]

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23 The word 'formal' in formal languages means
[A] they are unnecessary, in reality
[B] the symbols used have well-defined meaning
[C] only the form of the string of symbols is significant
[D] none of the above

Answer: Option [C]
24 The major difference between a Moore and a Mealy machine is that
[A] the output of the former depends only on the present state
[B] the output of the former depends only on the current input
[C] the output of the former depends on the present state and the current input
[D] none of the above

Answer: Option [A]
25 Choose the correct statements.
[A] Any given Mealy machine has an equivalent Moore machine.
[B] Any given Moore machine has an equivalent Mealy machine.
[C] Moore and Mealy machines are FSM's with output capability.
[D] All of the above

Answer: Option [D]
26 Which of the following pairs of regular expressions are equivalent?
[A] x* and x*x
[B] 1(01)* and (10)*1
[C] x(xx)* and (xx)*x
[D] all of the above

Answer: Option [D]
27 An FSM can be considered a TM

Choose the correct statements.

[A] of finite tape length, without rewinding capability and unidirectional tape movement
[B] of finite tape lengths rewinding capability and unidirectional tape movement
[C] of finite tape length, rewinding capability and bidirectional tape movement
[D] of finite tape length, without rewinding capability and bidirectional tape movement

Answer: Option [A]
28 The language of all words (made up of a’s and b’s) with at least two a’s can be described by the regular expression
[A] b*ab*a(a+b)*
[B] (a+b)*ab*a(a+b)*
[C] (a+b)*a(a+b)*a(a+b)*
[D] all of the above

Answer: Option [D]
29 The following CFG
S → aS | bS | a | b

is equivalent to the regular expression

[A] (a+b)*
[B] (a+b)(a+b)*
[C] (a+b)*(a+b)
[D] All of the above

Answer: Option [D]
30 Choose the correct statements.
[A] All languages can be generated by CFG.
[B] Any regular language has an equivalent CFG.
[C] Some non-regular languages can’t be generated by any CFG.
[D] (B) and (C)

Answer: Option [D]

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