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Free download in PDF Projectile Motion Multiple Choice Questions and Answers for competitive exams. These short objective type questions with answers are very important for Board exams as well as competitive exams like IIT-JEE, AIIMS etc. These short solved questions or quizzes are provided by Gkseries.
(1)
A ball is projected with velocity 10 m/sec at angle of 30o with the horizontal surface. The speed of the ball after 1 second will be
(Use g=10m/sec2)
[A]
5 m/sec
[B]
20 m/sec
[C]
8 m/sec
[D]
10 m/sec
(2)
A ball is projected with velocity 10 m/sec at angle of 30o with the horizontal surface. The range of the projectile is
[A]
10 m
[B]
10√3m
[C]
20√3m
[D]
40√3m
(3)
A stone is projected horizontally with a velocity 9.8m/s from a tower of height 100m. Its speed 1 s after projection is
[A]
9.8m/s
[B]
4.9m/s
[C]
9.8√2m/s
[D]
4.9√2m/s
(4)
An aeroplane flying horizontally at an altitude of 490m with a speed of 180km/h drops a bomb. The horizontal distance at which it hits the ground is(g=9.8m/s²)
[A]
500m
[B]
1000m
[C]
250m
[D]
None of the above
(5)
Two particles are projected with same velocity but at angles of projection (45-θ) and (45+θ). Then their horizontal ranges are in the ratio of
[A]
1:2
[B]
2:1
[C]
1:1
[D]
90/2 θ
(6)
The motion of a projectile is described by the equation y=ax - bx². The range of projectile is
[A]
a²/b²
[B]
a/2b
[C]
a/b
[D]
None Of The Above
(7)
For a projectile fired with a certain velocity, the Maximum possible Range and the Maximum height attainable are related as
[A]
Rmax=2Hmax
[B]
Rmax=Hmax/2
[C]
Rmax=3Hmax
[D]
None Of The Above
(8)
A ball projected at an angle θ, attains a maximum height H1 and if the ball is projected at angle of (90-θ) and the maximum height attained by the ball is H2.
Then the range of projectile will be
[A]
R= √H1H2
[B]
R= √H1H2 /2
[C]
R= 3√H1H2
[D]
None of these
(9)
A ball is projected with velocity 10 m/sec at angle of 30o with the horizontal surface. The maximum height attained by the projectile is
[A]
5 m
[B]
10 m
[C]
15 m
[D]
20 m
(10)
A ball is projected with velocity 10 m/sec at angle of 30o with the horizontal surface. The time taken by ball to reach the ground is
[A]
1 sec
[B]
2 sec
[C]
3 sec
[D]
None Of The Above
(11)
A ball is projected with velocity 10 m/sec at angle of 30o with the
horizontal surface. The angle made by the line joining point of projection with the point of maximum height is
[A]
tanˉ¹ 2/√3
[B]
tanˉ¹ 1/2√3
[C]
tanˉ¹ √3
[D]
tanˉ¹ 1/√3
(12)
The angle of projection for the range of projectile to be equal to its maximum height is
[A]
θ=tanˉ¹ (2)
[B]
θ=tanˉ¹ (3)
[C]
θ=tanˉ¹ (4)
[D]
None of the above
(13)
A body is projected with kinetic energy E so as to attain maximum horizontal range. Its potential energy at the highest point is
[A]
E
[B]
E/2
[C]
2E
[D]
√2E
(14)
A gun with a muzzle velocity of 500 m/s shoots a bullet at a target 50m away. To hit the target the gun should be aimed (g=10m/s²)
[A]
directly towards the target along the line joining the gun and bird
[B]
10 cm high above the target
[C]
5 cm high above the target
[D]
none of these
Answer: 5 cm high above the target
(15)
For a body thrown horizontally from the top of a tower,
[A]
the time of flight depends on both h and v
[B]
the horizontal Range depends only on v but not on h
[C]
the horizontal Range depends on both v and h
[D]
None of these
Answer: the horizontal Range depends on both v and h
(16)
A body is projected horizontally from a height of 78.4m with a velocity 10m/s. The angle made by velocity vector with x axis after
[A]
4 seconds is
[B]
tanˉ¹3
[C]
tanˉ¹4
[D]
tanˉ¹5
(17)
A body is projected vertically downwards with the velocity 5m/s from a height of 60m. Its time of descent is
[A]
2s
[B]
3s
[C]
4s
[D]
5s
(18)
A body is thrown with the velocity (4i + 3j) m/s. Its maximum height is (g=10m/s²)
[A]
2.5m
[B]
0.8m
[C]
0.9m
[D]
0.45m
(19)
A body projected with velocity 30m/s reaches its maximum height in 1.5s. Its range is (g=10m/s²)
[A]
45m
[B]
108m
[C]
45√3m
[D]
54m
(20)
The acceleration of a projectile relative to another projectile is
[A]
-g
[B]
g
[C]
0
[D]
None Of The Above
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