August 2023

In the circuit shown, the breakdown voltage and the maximum current of the Zener diode are 20 V and 60 mA, respectively

In the circuit shown, the breakdown voltage and the maximum current of the Zener diode are 20 V and 60 mA, respectively

Q. In the circuit shown, the breakdown voltage and the maximum current of the Zener diode are 20 V and 60 mA, respectively. The values of 𝑅1 and 𝑅𝐿 are 200 Ξ© and 1 kΞ©, respectively. What is the range of Vi that will maintain the Zener diode in the β€˜on’ state? Ans: 24 V

In the circuit shown, the breakdown voltage and the maximum current of the Zener diode are 20 V and 60 mA, respectively Read More Β»

Two identical copper wires W1 and W2, placed in parallel as shown in the figure, carry currents I and 2I, respectively, in opposite directions

Two identical copper wires W1 and W2, placed in parallel as shown in the figure, carry currents I and 2I, respectively, in opposite directions

Q. Two identical copper wires W1 and W2, placed in parallel as shown in the figure, carry currents I and 2I, respectively, in opposite directions. If the two wires are separated by a distance of 4r, then the magnitude of the magnetic field ⃗B→ between the wires at a distance r from W1 is Solution:

Two identical copper wires W1 and W2, placed in parallel as shown in the figure, carry currents I and 2I, respectively, in opposite directions Read More Β»

A single bit, equally likely to be 0 and 1, is to be sent across an additive white Gaussian noise (AWGN) channel with power spectral density 𝑁0/2.

A single bit, equally likely to be 0 and 1, is to be sent across an additive white Gaussian noise (AWGN) channel with power spectral density 𝑁0/2.

Q. A single bit, equally likely to be 0 and 1, is to be sent across an additive white Gaussian noise (AWGN) channel with power spectral density 𝑁0/2. Binary signaling, with 0 ↦ 𝑝(𝑑) and 1 ↦ π‘ž(𝑑), is used for the transmission, along with an optimal receiver that minimizes the bit-error probability. Let πœ‘1(𝑑),

A single bit, equally likely to be 0 and 1, is to be sent across an additive white Gaussian noise (AWGN) channel with power spectral density 𝑁0/2. Read More Β»

. In the circuit shown, if 𝑣(𝑑) = 2 sin(1000 𝑑) volts, 𝑅 = 1 kΞ© and 𝐢 = 1 πœ‡F, then the steady-state current 𝑖(𝑑), in milliamperes (mA), is

In the circuit shown, if 𝑣(𝑑) = 2 sin(1000 𝑑) volts, 𝑅 = 1 kΞ© and 𝐢 = 1 πœ‡F, then the steady-state current 𝑖(𝑑), in milliamperes (mA), is

Q. In the circuit shown, if 𝑣(𝑑) = 2 sin(1000 𝑑) volts, 𝑅 = 1 kΞ© and 𝐢 = 1 πœ‡F, then the steady-state current 𝑖(𝑑), in milliamperes (mA), is (A) sin(1000 𝑑) +   cos(1000 𝑑) (B) 2 sin(1000 𝑑) + 2 cos(1000 𝑑) (C) 3 sin(1000 𝑑) + cos(1000 𝑑) (D) sin(1000 𝑑) +

In the circuit shown, if 𝑣(𝑑) = 2 sin(1000 𝑑) volts, 𝑅 = 1 kΞ© and 𝐢 = 1 πœ‡F, then the steady-state current 𝑖(𝑑), in milliamperes (mA), is Read More Β»

CA

5 August 2023 Current Affairs – The Day’s Top News | GKSERIES

Current AffairsΒ is the most important area in all competitive exams. But the difficulty level is very high. That’s why; many aspirants get confused, how to select Current Affairs for Preparation of Competitive Examination? In this Post,Β Daily Current Affairs 5 AugustΒ 2023,Β we have tried to cover each and every point and also included all important facts from

5 August 2023 Current Affairs – The Day’s Top News | GKSERIES Read More Β»

Consider the line integral

Consider the line integral

Q. Consider the line integral ∫(π‘₯𝑑𝑦 βˆ’ 𝑦𝑑π‘₯) 𝐢 the integral being taken in a counterclockwise direction over the closed curve 𝐢 that forms the boundary of the region 𝑅 shown in the figure below. The region 𝑅 is the area enclosed by the union of a 2 Γ— 3 rectangle and a semi-circle of

Consider the line integral Read More Β»

Scroll to Top