In the given figure, AP is angle bisector of ∠CAE, CP = 7 cm and PE = 8 cm. find the length of AB (a) 32 (b) 25 (c) 49 (d) 56 Sol: ∠BAC = ∠CEA, In ∆ABC and ∆ABE, AE = 4x, AC = 3.5x ∆ABC ~ ∆ABE ∠B = common. BC/AB=AC/AE BC/AB=3.5X/4X (AB)² […]
If 5x – 3y = x + 3y, then 3x+6y/3x-y (a) 1 (b) 2 (c) 3 (d) 4 Sol:
A takes as much time as B and C together to complete a work. While A and B together can do this piece of work in 10 days. C alone can do this piece of work in 50 days. In how many days will this work be completed by B alone? (a) 20 days (b)
In a 600m race, A can beat B by 60 m and in a race of 500 m. B can beat C by25 m. By how many metres will A beat C in 400 m race (a) 56 m (b) 60 m (c) 58 m (d) 54 m Sol: A:B= 600:540= 10:9 B:C = 500:475
In a 600m race, A can beat B by 60 m and in a race of 500 m. B can beat C by25 m Read More »
The remainder of is 2180+590/41 is (a) 0 (b) 33 (c) 1 (d) 17 Sol: (ax+bx) if x are odd then the number is completely divisible by a+b. 16 + 25 = 41. So remainder=0.
The average weight of 4 men A, B, C and D is 67 kg. Another man E joins the groups and the average now becomes 65 kg. If another man F, whose weight is 4 kg more than that of E, replaces A, then average weight of B, C, D, E and F becomes 64
A marked price of a shirt and a trouser are in the ratio 7: 13. the shopkeeper: gives 28.56% discount on the shirt and some percent discount on the trouser which is equal to a total discount of 18.18% on the set of a shirt and a trouser the discount offered on the trouser i
In a triangle ABC, P and Q are the mid points of AB and BC respectively. Point G and H l ie’s on AC such that they are the mid-point of PR and QR respectively. Here R is a point outside the triangle. Then what is the Ratio of area ∆ ABC : area ∆
Two persons A and B started a work and after 10 days B left the work. Two days after B left, C joined A, and the total work was completed in ‘ N’ days. Each person completes an equal share of the work. It is known that A and B together can complete the work
