A seller bought x kg of apple for Rs.2000 and also bought (x + 5) kg of oranges for Rs.1800 and the seller sold each kg

A seller bought x kg of apple for Rs.2000 and also bought (x + 5) kg of oranges for Rs.1800 and the seller sold each kg

A seller bought x kg of apple for Rs.2000 and also bought (x + 5) kg of oranges for Rs.1800 and the seller sold each kg of apple and orange at a profit of 40% and 25% and the selling price of each kg of orange is Rs.150. Find selling price of (x – 5) kg of apple.

a) Rs.1800

b) Rs.1400

c) Rs.2500

d) Rs.2000

e) None of these

Sol:

Cost price of each kg of apple = 2000/x

Cost price of each kg of orange = 1800/(x + 5)

1800/(x + 5) * 125/100 = 150

1800/(x + 5) * 5/4 = 150

x + 5 = 15

x = 10

Cost price of each kg of apple = 2000/10 =

Rs.200

Required selling price = (10 – 5) * 200 * 140/100

= 5 * 200 * 7/5 = Rs.1400

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