If cosα + cosβ = A and sinα + sinβ = B, find sin(α – β). (a) A2+B2-2/2 (b) A2+B2+2/2 (c) A² – B² + 1 (d) A² + B² – 4 Sol: Put α = β = 0 A = 2 B = 0 Sin0 = 0 Only option D satisfies (4) + 0 […]
If cosα + cosβ = A and sinα + sinβ = B, find sin(α – β) Read More »
In a trapezium ABCD, ∠DAB = 60° and ∠CBA = 30°, AB || CD, AD = 22 cm, CD = 11 √3cm . Find the area of trapezium? Answer: Option D
Rs. 17,325 has to be divided between x, y & z such that x gets 4/5 of what y gets and y gets 2/3 of what z gets. How much does z get over x (in Rs.) (a) Rs. 3675 (b) Rs. 3668 (c) Rs. 3661 (d) Rs. 3654 Sol:
MNOP is a cyclic quadrilateral. The angle bisector of ∠PMN and ∠PON meets the circle at point A and B respectively. Find the value of ∠AMB? (a) 45° (b) 90° (c) 60° (d) 120° Sol: Assume any angle ∠PMN = 60° Angle made by arc BN = 60° at So angle made by arc BN
If (a+b–c –5)² + (b+c–a–9)² +(c+a–b – 11)² = 0 then √a+b+c = ? (a) 6 (b) 4 (c) 2 (d) 5 Sol: a + b – c = 5 b + c – a = 9 c + a – b = 7 a + b + c = 25
If (a+b–c –5)² + (b+c–a–9)² +(c+a–b – 11)² = 0 then √a+b+c Read More »
A trader marks up in his goods by 120% and offers 30% discount. What will be the selling price (in Rs.), if the cost price is Rs. 1350? (a) Rs. 2059 (b) Rs. 2069 (c) Rs. 2079 (d) Rs. 2089 Sol:
Train A takes 45 minutes more than train B to travel a distance of 675 km. Due to engine trouble speed of train B falls by a quarter, so it takes 30 minutes more than train A to complete same journey. What is the speed of train A (in km/h)? (a) 150 (b) 125 (c)
Two dice are thrown. Find the probability that a multiple of 3 occurs on one dice and a multiple of 2 occurs on the other. (a) 1/2 (b) 13/36 (c) 1/3 (d) 11/36 Sol: We have a total of 11 favorable cases viz. 2,3 2,6, 4,3 4,6 6,3 3,6 6,4 3,4 6,2 3,2 and 6,6
Alloy A contains copper and zinc in the ratio of 4: 3 and alloy B contains copper and zinc in the ratio 5:2. A and B are taken in the ratio of 5: 7 and melted to form a new alloy. The percentage of zinc is the new alloy as closest to (a) 34.5% (b)
Find the mean of the first 10 even integers. (a) 11 (b) 9 (c) 12 (d) 10 Sol: First 10 odd integers: 2, 4, 6, 8, 10, 12, 14, 16, 18, 20 Mean = Sum of the first 10 odd integers/Number of such integers = (2 + 4 + 6 + 8 + 10 +
