| Question | Find the average of first 5 consecutive even numbers starting from 2 to 10, where the last even number is 10. | |
| Type | multiple_choice | |
| Option | 1 | incorrect |
| Option | 6 | correct |
| Option | 2 | incorrect |
| Option | 8 | incorrect |
| Solution | The average of first n consecutive even numbers starting from 2 to X, where the last even number is X, is given by: = (X+2)/2 Here, X=10 So, the required average = (10+2)/2 = 12/2 =6 | |
