If (a+b)=2,(b+c)=1, and (c+a)=3 then find a3+b3+c3 ?
(a) 3
(b) 1
(c) 8
(d) 9
Sol:
a + b = 2
b + c = 1
c + a = 3
(a + b + c) = 3
Cube both sides
a³ + b³ + c³ + 3(a + b) (b + c) (c + a) = 27
a³ + b³ + c³ = 27 – 18
= 9
Take Mock Tests
| Government Schemes Mock Test | Start Test! |
| Political Science Mock Test – 42 | Start Test |
| History Test – 190 | Start Test |
| Quantitative Aptitude Test | Start Test! | Data Interpretation - Mock Test | Start Test! |
| General Awareness - Mock Test | Start Test! |
| Reasoning Ability - Mock Test | Start Test! |
We will be happy to hear your thoughts