Mixture X contains 70% of juice and the remaining water, mixture Y of 64 litres contains juice and water in the ratio

Mixture X contains 70% of juice and the remaining water, mixture Y of 64 litres contains juice and water in the ratio of 3:1, if both are mixed in the third container, then the quantity of water in the final mixture is 29.5liters. Find the total volume of Mixture X (in litres)?

A.            40 litres

B.            35 litres

C.            50 litres

D.            60 litres

E.            45 litres

Sol:

Let the initial quantity of mixture X =100x

Amount of juice in the mixture =70% of 100x

=70x

The remaining 30x is water.

Amount of juice in the another mixture = (64/4) ×

3 = 48litres

Remaining 16litres are water.

It is given that,

30x+16 =29.5

30x =13.5

x=0.45

Total quantity of mixture X =100x = 100(0.45) =

45litres