If (a+b–c –5)² + (b+c–a–9)² +(c+a–b – 11)² = 0 then √a+b+c
If (a+b–c –5)² + (b+c–a–9)² +(c+a–b – 11)² = 0 then √a+b+c = ? (a) 6 (b) 4 (c) 2 (d) 5 Sol: a + b – c = 5 b + c – a = 9 c + a – b = 7 a + b + c = 25
If (a+b–c –5)² + (b+c–a–9)² +(c+a–b – 11)² = 0 then √a+b+c Read More »










