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A shopkeeper marked an article at 50% above its cost price and sold it after giving two successive discounts of 10% and 20% respectively. If the shopkeeper gets the profit of Rs.960, then find the marked price of the article? a) Rs.18000 b) Rs.20000 c) Rs.15000 d) Rs.22000 e) Rs.12000 Sol: CP * ...

Radius of the circle is 21 m and the area of the circle is 54 m2 less than the sum of the lateral surface area and the total surface area of the cube. Find the volume of the cube. a) 729 m3 b) 2197 m3 c) 1728 m3 d) 1000 m3 e) None of these Sol: Area of the circle = 22/7 * 21 * ...

1449 ÷ 23 + (5365 ÷ 37) + 1958 ÷ 89 = ? a) 240 b) 230 c) 250 d) 280 e) 220 1449 ÷ 23 + (5365 ÷ 37) + 1958 ÷ 89 = ? 63 + 145 + 22 = ? 230 = ?

Q. √4489 + √1849 - √841 = ?2 a) 7 b) 5 c) 8 ...

Q. I. x2 – 34x + 289 = 0 II. y3 = 702 + 1691/2 a) x> y b) y> x c) x ≥ y d) x ≤ y e) x = y or relation cannot be established Sol: I. x2 – 34x + 289 = 0 x2 – 17x – 17x + 289 = 0 x(x – 17) – 17(x – 17) = 0 x = 17 II. y3 = 702 + 1691/2 y3 = ...

In a mixture of milk and water, milk is 16 L more than water and the cost of the mixture is Rs.33(1/3). If the cost of pure milk is Rs.50 per L, then find the total quantity of the mixture. a) 36 L ...

Average weight of 13 students in a class is 55 kg, out of which the average weight of the first 6 students is 53 kg and the average weight of next 6 students out of the remaining 7 is 56 kg, then find the weight of the remaining one student. ...

Ratio of total goals scored by Messi against teams A to B is 3: 5 and the ratio of goals scored by Messi against teams B to C are 3: 2. If the difference between goals scored by him against A and C is 5, then find the total number of goals scored by Messi against all the three teams together. a) ...

1. Volume of a sphere is 38808 cm3. Find the ratio of its volume to its surface area. a) 7: 2 b) 21: 1 c) Cannot be determined d) 7: 1 e) 21: 2 Sol: Let the radius of the sphere = ‘r’ cm So, (4/3) * (22/7) * r3 = 38808 r3 = 9261 r = 21 cm The ratio of the volume of the sphere to its surface ...

Q. I. x2 – 47x + 480 = 0 II. y = √(31y – 240) a) x = y or relation cannot be established b) y> x c) x ≥ y d) x ≤ y e) x> y Sol: I. x2 – 47x + 480 = 0 x2 – 32x – 15x + 480 = 0 x(x – 32) – 15(x – 32) = 0 x = 15 or 32 II. y = √(31y – 240) ...