A timber pile of length 8 m and diameter 0.2 m is driven with a 20 kN drop hammer, falling freely from a height of 1.5 m. The total penetration of the pile in the last 5 blows is 40 mm

A timber pile of length 8 m and diameter 0.2 m is driven with a 20 kN drop hammer, falling freely from a height of 1.5 m. The total penetration of the pile in the last 5 blows is 40 mm

Q. A timber pile of length 8 m and diameter 0.2 m is driven with a 20 kN drop hammer, falling freely from a height of 1.5 m. The total penetration of the pile in the last 5 blows is 40 mm. Use the Engineering News Record expression. Assume a factor of safety of 6

A timber pile of length 8 m and diameter 0.2 m is driven with a 20 kN drop hammer, falling freely from a height of 1.5 m. The total penetration of the pile in the last 5 blows is 40 mm Read More »

Constant head permeability tests were performed on two soil specimens, S1 and S2. The ratio of height of the two specimens (LS1:LS2) is 1.5

Constant head permeability tests were performed on two soil specimens, S1 and S2. The ratio of height of the two specimens (LS1:LS2) is 1.5

Q. Constant head permeability tests were performed on two soil specimens, S1 and S2. The ratio of height of the two specimens (LS1:LS2) is 1.5, the ratio of the diameter of specimens (DS1:DS2) is 0.5, and the ratio of the constant head (hS1:hS2) applied on the specimens is 2.0. If the discharge from both the

Constant head permeability tests were performed on two soil specimens, S1 and S2. The ratio of height of the two specimens (LS1:LS2) is 1.5 Read More »

A 2 m × 4 m rectangular footing has to carry a uniformly distributed load of 120 kPa.

A 2 m × 4 m rectangular footing has to carry a uniformly distributed load of 120 kPa. As per the 2:1 dispersion method of stress distribution, the increment in vertical stress (in kPa) at a depth of 2 m

Q. A 2 m × 4 m rectangular footing has to carry a uniformly distributed load of 120 kPa. As per the 2:1 dispersion method of stress distribution, the increment in vertical stress (in kPa) at a depth of 2 m below the footing is     Solution: Increment in the vertical stress =120×2×4/(2+h)(4+h) =120×2×4/(2+2)(4+2) =

A 2 m × 4 m rectangular footing has to carry a uniformly distributed load of 120 kPa. As per the 2:1 dispersion method of stress distribution, the increment in vertical stress (in kPa) at a depth of 2 m Read More »

DAILY CURRENT AFFAIRS -

1 August 2023 Current Affairs – The Day’s Top News | GKSERIES

Current Affairs is the most important area in all competitive exams. But the difficulty level is very high. That’s why; many aspirants get confused, how to select Current Affairs for Preparation of Competitive Examination? In this Post, Daily Current Affairs 1 August 2023, we have tried to cover each and every point and also included all important facts from

1 August 2023 Current Affairs – The Day’s Top News | GKSERIES Read More »

At the foot of a spillway, water flows at a depth of 23 cm with a velocity of 8.1 m/s, as shown in the figure

At the foot of a spillway, water flows at a depth of 23 cm with a velocity of 8.1 m/s, as shown in the figure

Q. At the foot of a spillway, water flows at a depth of 23 cm with a velocity of 8.1 m/s, as shown in the figure. The flow enters as an M-3 profile in the long wide rectangular channel with bed slope =  1/1800 and Manning’s n = 0.015. A hydraulic jump is formed at a

At the foot of a spillway, water flows at a depth of 23 cm with a velocity of 8.1 m/s, as shown in the figure Read More »

A confined aquifer of 15 m constant thickness is sandwiched between two aquicludes as shown in the figure (not drawn to scale)

A confined aquifer of 15 m constant thickness is sandwiched between two aquicludes as shown in the figure (not drawn to scale)

Q. A confined aquifer of 15 m constant thickness is sandwiched between two aquicludes as shown in the figure (not drawn to scale). The heads indicated by two piezometers P and Q are 55.2 m and 34.1 m, respectively. The aquifer has a hydraulic conductivity of 80 m/day and its effective porosity is 0.25. If the

A confined aquifer of 15 m constant thickness is sandwiched between two aquicludes as shown in the figure (not drawn to scale) Read More »

GST E-Invoice Rule Update: Companies with Turnover > ₹5 Crore Now Mandated to Generate E-Invoices

GST E-Invoice Rule Update: Companies with Turnover > ₹5 Crore Now Mandated to Generate E-Invoices

GST E-Invoice Rule Update: Companies with Turnover > ₹5 Crore Now Mandated to Generate E-Invoices: The Central Board of Indirect Taxes and Customs (CBIC) announced a substantial adjustment in India’s Goods and Services Tax (GST) laws on July 28, 2023. As per the new guidelines, companies with a turnover of more than ₹5 crore will

GST E-Invoice Rule Update: Companies with Turnover > ₹5 Crore Now Mandated to Generate E-Invoices Read More »

A broad gauge railway line passes through a horizontal curved section (radius = 875 m) of length 200 m. The allowable speed on this portion is 100 km/h. For calculating the cant

A broad gauge railway line passes through a horizontal curved section (radius = 875 m) of length 200 m. The allowable speed on this portion is 100 km/h. For calculating the cant

Q. A broad gauge railway line passes through a horizontal curved section (radius = 875 m) of length 200 m. The allowable speed on this portion is 100 km/h. For calculating the cant, consider the gauge as centre-to-centre distance between the rail heads, equal to 1750 mm. The maximum permissible cant (in mm, round off

A broad gauge railway line passes through a horizontal curved section (radius = 875 m) of length 200 m. The allowable speed on this portion is 100 km/h. For calculating the cant Read More »

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