The maximum data rate that a medium of 10 KHz and signal to noise ratio of 30dB is roughly

A 10Kbps
B 30Kbps
C 100Kbps
D 3Kbps
Answer & Explanation
Option: [B]

Using channel capacity formula of Shannon : we get

C = W * log2(1 + S/N)

30 dB S/N = 1000 S/N

C = 3000*log2(1 + 1000)

C = 30 Kbps

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