The smallest integer that can be represented by an 8-bit number in 2’s complement form is

Answer & Explanation

Answer: Option [B]

The range of N bit two's complement number is given by -(2^n-1)....0....(2^n-1-1)

So, range of 8 bit 2's complement number is -(2^8-1)....0....(2^8-1-1)

-128....0....127

Hence the smallest integer that can be represented by an 8-bit number in 2’s complement form is -128