Answer & ExplanationAnswer: Option [A]
L1=Φ. So L1L2*=Φ. Though multiplication of any language with Φ results in Φ.
Again ε∈L1*. So, L1L2* U L1* = ΦUε
Concatenation Φ with anything results in Φ. Though Φ is an empty string.
So, ΦUε = {ε}
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