NCERT Solutions for class 12 Maths | Chapter 2 - Inverse Trigonometric Functions

(1) cot-1(1)
[A] π/3
[B] π/4
[C] π/2
[D] 0
Answer: π/4
(2) tan-1(√3)
[A] π/6
[B] π/3
[C] 2π/3
[D] 5π/6
Answer: π/3

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(3) tan-1 √3 – sec-1 (-2) is equal to
[A] π
[B] –π/3
[C] π/3
[D] 2π/3
Answer: –π/3
(4) Princal value of tan-1 (-1) is
[A] π/4
[B] −π/2
[C] 5π/4
[D] −π/4
Answer: −π/4
(5) sin-1 x = y Then
[A] 0 ≤ y ≤ π
[B] –π/2 ≤ y ≤ π/2
[C] 0 < y < π
[D] –π/2 < y < –π/2
Answer: –π/2 ≤ y ≤ π/2
(6) tan-11/2 + tan-1 2/11 = tan-1 a then a = ?
[A] 1/4
[B] 1/2
[C] 3/4
[D] 1
Answer: 3/4
(7) The domain of the following f(x) = is
[A] [0, 1]
[B] [-1, 1]
[C] [-, 0]
[D] [0, 1]
Answer: [0, 1]
(8) The domain of the function defined by f (x) = sin-1 is
[A] [1, 2]
[B] [-1, 1]
[C] [0, 1]
[D] None of these
Answer: [1, 2]
(9) The value of sin (2 tan-1 (.75)) is equal to
[A] .75
[B] 1.5
[C] .96
[D] sin 1.5
Answer: .96
(10) If |x| ≤ 1, then 2 tan-1 x + sin-1(2x/1+x2) is equal to
[A] 4 tan-1 x
[B] π2
[C] 0
[D] π
Answer: 4 tan-1 x
(11) cos-1(1/2)
[A] –π/3
[B] π/3
[C] π/2
[D] 2π/3
Answer: π/3
(12) cos-1(√3/2)
[A] 5π/6
[B] π/6
[C] 4π/9
[D] 2π/3
Answer: 5π/6
(13) cot-1(-√3)
[A] 5π/6
[B] π/3
[C] π/2
[D] π/4
Answer: 5π/6
(14) The principle value of sin-1 √3/2 is
[A] 2π/3
[B] π/6
[C] π/4
[D] π/3
Answer: π/3
(15) Princal value of cos-1(−1/√2)
[A] 3π/4
[B] 5π/4
[C] –π/4
[D] None of these
Answer: 3π/4
(16) If y = sec-1 x then
[A] 0 ≤ y ≤ π
[B] 0 ≤ y ≤ π/2
[C] –π/2 < y < π/2
[D] None of these
Answer: None of these
(17) sin[π/3 – sin-1(-1/2)] is equal to
[A] 1/2
[B] 1/3
[C] 1/4
[D] 1
Answer: 1
(18) The value of cos-1(1/2) + 2sin-1(1/2) is equal to
[A] π/4
[B] π/6
[C] 2π/3
[D] 5π/6
Answer: π/6
(19) tan-11/2 + tan-11/3 =
[A] π/4
[B] π/2
[C] π/3
[D] π
Answer: π/4
(20) Which of the following is the principal value branch of cosec-1 x?
[A] (−π/2, π/2)
[B] (0, π) – {π/2}
[C] [−π/2, π/2]
[D] [−π/2, π/2] – [0]
Answer: [−π/2, π/2] – [0]

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