NCERT Solutions for class 12 Maths | Chapter 6 - Application of Derivatives
Questions
1
The combined resistance R of two resistors R1 and R2 (R1, R2 > 0) is given by 1/R=1/R1+1/R2. If R1 + R2 = C (a constant), then maximum resistance R is obtained if
Answer:R1 = R2
2
Find the height of a cylinder, which is open at the top, having a given surface area, greatest volume and of radius r.
Answer:r
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3
The function f(x) = x + 4/x has
Answer:local minima at x = 2, and local maxima at x = -2
4
The coordinates of the point on the parabola y2 = 8x which is at minimum distance from the circle x2 + (y + 6)2 = 1 are
Answer:(2, -4)
7
The position of a point in time ‘t’ is given by x = a + bt – ct2, y = at + bt2. Its acceleration at time ‘t’ is
(a)
(b)
(c)
Answer:![]()
8
The sides of an equilateral triangle are increasing at the rate of 2 cm/s. The rate at which the area increases, when the side is 10 cm, is
Answer:10√3 cm2/s
9
The radius of a cylinder is increasing at the rate of 3 m/s and its height is decreasing at the rate of 4 m/s. The rate of change of volume when the radius is 4 m and height is 6 m, is
Answer:80π cu m/s
11
Find the approximate value of f(3.02), where f(x) = 3x2 + 5x + 3
Answer:45.46
12
If the radius of a sphere is measured as 9 cm with an error of 0.03 cm, then find the approximating error in calculating its volume.
Answer:9.72π cm3
13
If there is an error of a% in measuring the edge of a cube, then percentage error in its surface area is
Answer:a/2 %
14
If there is an error of 2% in measuring the length of a simple pendulum, then percentage error in its period is
Answer:1%
15
Tangents to the curve x2 + y2 = 2 at the points (1, 1) and (-1, 1) are
Answer:perpendicular
16
Find a point on the curve y = (x – 2)2. at which the tangent is parallel to the chord joining the points (2, 0) and (4, 4).
Answer:(3, 1)
17
The tangent to the curve y = x2 + 3x will pass through the point (0, -9) if it is drawn at the point
Answer:(-3, 0)
18
The tangent to the curve y = 2x2 -x + 1 is parallel to the line y = 3x + 9 at the point
Answer:(1, 2)
19
The two curves x3 – 3xy2 + 5 = 0 and 3x2y – y3 – 7 = 0
Answer:cut at right angles
20
The tangent to the parabola x2 = 2y at the point (1, 1/2) makes with the x-axis an angle of
Answer:45°