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NCERT Solutions for class 12 Maths | Chapter 8 - Application of Integrals

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Free download in PDF Class 12 Maths Chapter 8 Application of Integrals Multiple Choice Questions and Answers for Board, JEE, NEET, AIIMS, JIPMER, IIT-JEE, AIEE and other competitive exams. MCQ Questions for Class 12 Maths with Answers were prepared based on the latest exam pattern. These short solved questions or quizzes are provided by Gkseries. These will help the students for preparation of their examination./p>

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(1) The area of the region bounded by the curve y= and x-axis is
[A] 8π sq. units
[B] 2π sq. units
[C] 16π sq. units
[D] 6π sq. units
Answer: 2π sq. units
(2) Area bounded by the ellipse 1 is
[A] 6π sq. units
[B] 3π sq. units
[C] 12π sq. units
[D] None of these
Answer: 6π sq. units

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(3) Area of triangle whose two vertices formed from the x-axis and line y = 3 – |x| is,
[A] 9 sq. units
[B] 3/2 sq. units
[C] 3 sq. units
[D] None of these
Answer: None of these
(4) The area bounded by the line y = 2x – 2, y = -x and x-axis is given by
[A] 9/2 sq. units
[B] 43/6 sq. units
[C] 35/6 sq. units
[D] None of these
Answer: None of these
(5) Area bounded by the curve y = cos x between x = 0 and x = 3π/2 is
[A] 1 sq. units
[B] 2 sq. units
[C] 3 sq. units
[D] 4 sq. units
Answer: 3 sq. units
(6) Find the area enclosed by parabola y2 = x and the line y + x = 2 and the x-axis.
[A] 5/6 sq. units
[B] 7/6 sq. units
[C] 6/7 sq. units
[D] 4/7 sq. units
Answer: 7/6 sq. units
(7) Area bounded by the curve y2 = 16x and line y = mx is 2/3 then m is equal to
[A] 3
[B] 4
[C] 1
[D] 2
Answer: 4
(8) The area bounded by the curve x = 3y2 – 9 and the line x = 0, y = 0 and y = 1 is
[A] 8 sq. units
[B] 8/3 sq. units
[C] 3/8 sq. units
[D] 3 sq. units
Answer: 8 sq. units
(9) The area bounded by the curve y2 = x, line y = 4 and y-axis is
[A] 16/3 sq. units
[B] 64/3 sq. units
[C] 7√2 sq. units
[D] none of these
Answer: 64/3 sq. units
(10) Area of the smaller region bounded by x2 + y2 = 9 and the line x = 1 is
[A] (2 – 3 sec-1 3) sq. units
[B] (√8 – 3sec-1 3) sq.units
[C] (9sec-1 3 – √8) sq. units
[D] (sec-1 3 – 3√8) sq.units
Answer: (9sec-1 3 – √8) sq. units
(11) Area of the region bounded by the curve y = x2 and the line y = 4 is
[A] 11/3 sq. units
[B] 32/3 sq. units
[C] 43/3 sq. units
[D] 47/3 sq. units
Answer: 32/3 sq. units
(12) The area bounded by the lines y = |x – 2|, x = 1, x = 3 and the x-axis is
[A] 1 sq. units
[B] 2 sq. units
[C] 3 sq. units
[D] 4 sq. units
Answer: 2 sq. units
(13) The area bounded by x = – 4y2 and x – 1 = -5y2 is
[A] 1 sq. unit
[B] 2/3 sq. units
[C] 2/3 sq. units
[D] 2 sq. units
Answer: 2/3 sq. units
(14) The area included between curves y = x2 – 3x + 2 and y = -x2 + 3x – 2 is
[A] 1/6 sq. units
[B] 1/2 sq. units
[C] 1 sq. units
[D] 1/3 sq. units
Answer: 1/3 sq. units
(15) The area bounded by the curves y = sin x, y = cos x and x = 0 is
[A] (√2 – 1) sq. units
[B] 1 sq. units
[C] √2 sq. units
[D] (1 + √2) sq. units
Answer: (√2 – 1) sq. units
(16) The area bounded by the curves x2 + y2 = 9 and y2 = 8x is
[A] 0 sq. units
[B] sq. units
[C] 16π sq. units
[D] None of these
Answer: sq. units
(17) The area enclosed between the curve y2 = 4x and the line y = x is
[A] 8/3 sq. units
[B] 4/3 sq. units
[C] 2/3 sq. units
[D] 1/2 sq. units
Answer: 8/3 sq. units
(18) The area of the region R = ((x, y) : |x| ≤ |y| and x2 + y2 ≤ 1) is
[A] 3π/8 sq. units
[B] 5π/8 sq. units
[C] π/2 sq. units
[D] π/8 sq. units
Answer: π/2 sq. units
(19) The area bounded by the curve y = x2 – 1 and the straight line x + y = 3 is
[A] 9/2 sq. units
[B] 4 sq. units
[C] 7√17/2 sq. units
[D] 17√17/6 sq. units
Answer: 17√17/6 sq. units
(20) The area enclosed by curve is
[A] 10π sq. units
[B] 20π sq. units
[C] 5π sq. units
[D] 4π sq. units
Answer: 20π sq. units

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