If 𝐀 = 2𝑥𝐢 + 3𝑦𝐣 + 4𝑧𝐤 and 𝑢 = 𝑥2 + 𝑦2 + 𝑧2, then div(𝑢𝐀) at (1, 1, 1) is
Q. If 𝐀 = 2𝑥𝐢 + 3𝑦𝐣 + 4𝑧𝐤 and 𝑢 = 𝑥2 + 𝑦2 + 𝑧2, then div(𝑢𝐀) at (1, 1, 1) is Ans: 45 Solution:
If 𝐀 = 2𝑥𝐢 + 3𝑦𝐣 + 4𝑧𝐤 and 𝑢 = 𝑥2 + 𝑦2 + 𝑧2, then div(𝑢𝐀) at (1, 1, 1) is Read More »










