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Direction: Following question contains two equations as I and II. You have to solve both equations and determine the relationship between them and give answer as, Q. I: 5x2 – 18x + 9 = 0 II: 4y2 + 9y - 9 = 0 ...

Sakshi invested Rs. 30000 in CI at the rate of x % per annum and Rs. 40000 is invested in SI at (x + 5) % rate of interest for one year if she received the total amount at the end of the year is Rs. 75500, then find the rate of interest per annum for Simple interest? A.8 % B.14 % C.10 % D.12 % E. ...

4/15 of 393 + 7/12 of 473 = ? × (1.99 + 1.01) A.127 B.137 C.157 D.177 E.147 Sol: 4/15 of 393 + 7/12 of 473= ?x (1.99 + 1.01) or, ? x 3 = (4/15) x 393 + (7/12) x 473 or, ? x 3 = (4/15) x390 + (7/12) x 473 or, ? x 3 = 104 + 276 or, ? = 380/3 = 126.667 = 127

Ragu’s monthly income is 2 times Reena’s monthly income. Reena’s monthly income is 20 % more than Ravi’s monthly income. Reena’s monthly income is Rs. 30000. Find Ragu’s annual income? A.Rs. 680000 B.Rs. 720000 C.Rs. 760000 D.Rs. 640000 E. None of these Sol: Ragu’s monthly ...

√(2809.001) ÷ 7.98 × (12.01)2 + 46.002 = ? A.1300 B.900 C.1000 D.1100 E.980 Sol: √2809.001 ÷ 7.98 x (12.01)2 + 46.002 = ? or, ? = √2809 ÷ 8 x (12)2 + 46 or, ? = (53/8) x (12)2 + 46 or, ? = 954 + 46 ? = 1000

(35% of 74000) ÷ ? = (123 % of 13.02)2 ×2.01 A.40 B.50 C.75 D.90 E.65 Sol: (35% of 74000) ÷ ? = (123% of 13.02)2 x 2.01 Or, (35x74000)/ 100 ÷ ? = 2 x 2 or, 25900 / ? = (15.99)2 × 2 or, (25900/?) = 16×16×2 ?= 25900 / (16×16×2) = 50.58 = 50

17.982 + 4.05 x 90.11 ÷ 4.98 = ? A.396 B.336 C.242 D.423 E.816 Sol: 17.982 + 4.05 x 90.114 ÷ 4.98 = ? 182 + 4 x (90/5) = ? 324 + 4 x 18 =? 324+72 =? ? = 396

A boat rowing at the speed of 24 kmph and the speed of stream is 6 kmph. If the boat covers a certain distance upstream and downstream in 32 hours, then find the distance? A.280 km B.300 km C.320 km D.360 km E. None of these Sol: Speed of boat in still water = 24 kmph ...

Direction: Find out the wrong number in the following number series. Q. 4, 5, ...

Direction: Find out the wrong number in the following number series. Q. 64, 96, 144, 216, 324, 496 A.496 B. 324 C.144 D. 96 E.64 Sol: 64 + (64 ÷ 2)=96 96 + (96 ÷ 2)=144 144 + (144 ÷ 2)=216 216 + (216 ÷ 2)=324 324 + (324 ÷ 2)=486