NCERT Solutions for class 12 Maths | Chapter 13 - Probability

(1) If P(x) = 2/15; y = 1, 2, 3, 4, 5, 0 otherwise then P|x = 1 or 2| is
[A] 1/15
[B] 2/15
[C] 1/5
[D] None of these
Answer: 1/5
(2) If one card is drawn out of 52 playing cards, the probability that it is an dice is
[A] 1/26
[B] 1/13
[C] 1/52
[D] 1/4
Answer: 1/13

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(3) Two number are chosen, one by one without replacement from the set of number A = {1, 2, 3, 4, 5, 6} then the probability that minimum value of two number chosen is less than 4 is
[A] 14/15
[B] 1/15
[C] 1/5
[D] 8/5
Answer: 1/15
(4) If A and B are events such that P (A∪B) = 3/4. P(A∩B) = 1/4, P(a) = 2/3 then P(AB) is
[A] 3/8
[B] 5/8
[C] 5/12
[D] 1/4
Answer: 5/8
(5) If P (a) = 3/8, P(b) = 1/2 and P(A∩B) = 1/4 then
[A] 1/4
[B] 1/3
[C] 3/4
[D] 3/8
Answer: 1/3
(6) If P(a) = 0,4, P(b) = 0.8 and P(B|A) = 0.6 then P(A∪B) is equal to
[A] 0.24
[B] 0.3
[C] 0.48
[D] 0.96
Answer: 0.96
(7) If P(a) = 7/10 P(b) = 7/10 and P(A∪B) = 7/10 then P (B|A) + P(A|B) equals
[A] 1/4
[B] 1/3
[C] 5/12
[D] 7/12
Answer: 7/12
(8) An urn contain’s balls of which 3 are red, 4 are blue and 2 are green, 3 balls are drawn at random without replacement from the urn. The probability that the 3 balls haye different colours is
[A] 1/3
[B] 2/7
[C] 1/21
[D] 2/23
Answer: 2/7
(9) The mean and the variance of binomial distribution are 4 and 2, respectively. Then the probability of 2 success
[A] 128/256
[B] 219/256
[C] 7/64
[D] 28/256
Answer: 7/64
(10) The probability of India w inning a test match against. West Indies is 1/2. Assuming independence from match to match the probability that in a match series India second win occurs at the third test is)
[A] 1/6
[B] 1/4
[C] 1/2
[D] 2/3
Answer: 1/4
(11) Five horse are in a race. Mr. A select two of the horses at random and best on them. The probability that Mr. A select the winning horses is
[A] 4/5
[B] 3/5
[C] 1/5
[D] 2/5
Answer: 2/5
(12) The chance of getting a doublet with 2 dice is
[A] 2/3
[B] 1/6
[C] 5/6
[D] 5/36
Answer: 1/6
(13) If A and B are two events such that P(a) ≠ 0 and then
[A] B ⊂ A
[B] B = φ
[C] A ⊂ B
[D] A ∩ B = φ
Answer: A ⊂ B
(14) P(A∩B) =
[A] 3/5
[B] 5/8
[C] 3/8
[D] 5/6
Answer: 5/6
(15) The probability of an event is 3/7. Then odd against the event is
[A] 4 : 3
[B] 7 : 3
[C] 3 : 7
[D] 3 : 4
Answer: 4 : 3
(16) Let A and B two event such that P(a) = 3/8, P(b) = 5/8 and P(A∪B) = 3/4. Then P(A|B).P(A’|B) is equal to
[A] 2/5
[B] 3/8
[C] 3/20
[D] 6/25
Answer: 6/25
(17) If P(a) =
[A] 3/47
[B] 5/49
[C] 2/3
[D] 1/4
Answer: 2/3
(18) If A and B are two independent events, then
[A] P(A∩B) = P(a) × P(b)
[B] P(AB) = 1 – P(A’) P(B’)
[C] P(AB) = 1 + P (A’) P(B’) P(A’)
[D]
Answer: P(A∩B) = P(a) × P(b)
(19) If P(a) = 3/8, P(b) = 1/3 and P(A∩B) = — then P (A’ ∩B’)
[A] 13/24
[B] 13/8
[C] 13/9
[D] 13/4
Answer: 13/24
(20) Three distinct numbers.are selected from First 100 natural numbers. The probability divisible by 2 and 3 is
[A] 9/25
[B] 4/35
[C] 4/55
[D] 4/1155
Answer: 4/1155

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