Simplification of Problems - Quantitative Aptitude Questions with Answers for IBPS PO

Answer: Option [C]

Answer: Option [D]

Let the number of chocolates each child got is x

Then, 120x/105 - x = 4

= (120x-105x)/105 = 4

= 15x = 420

So, x = 28

Thus each classmate got 28 + 4 = 32 chocolates

Answer: Option [A]

Let us take the total number of owls is = x

and total number of lions is = y

Then, x + y = 1460 --------(i)

We know that a owl has 2 legs and a lion has 4 legs.

So, the total number of legs of owl is = 2x

and the total number of legs of lion is = 4x

So, 2x + 4x = 4580 --------(ii)

Solving the equation (i) and (ii) we get,

x = 630 and y = 830

So the total number of owls is = 630

Answer: Option [B]

= 6/5 of 400 - 3/38 of 304

= 480 - 24

= 456

Answer: Option [C]

On the second day he spend Rs. 250. i.e. he earns Rs. 70

On the third day he again earn Rs. 320 and spend Rs. 70. Thus he save Rs. 70 again.

Thus it is seen that he save Rs. 70 in every 2 days.

So, he earn Rs. 1050 in 1050/70 x 2 = 30 days.